Question

please solve this question​

Answer 1

Answer:

$5)(81) {}^{0.16} \times (81) {}^{0.09} \\ = (81) {}^{0.25} = (81) {}^{ \frac{1}{4} } \\ = (3 {}^{4}) {}^{ \frac{1}{4} } = 3 \: \: ans \: \\ \\ \\ 6) (\frac{64}{25}) {}^{ \frac{3}{2} } = ( \sqrt{ \frac{8 \times 8}{5 \times 5} }) {}^{3} \\ = ( \frac{8}{5} ) {}^{3} = \frac{512}{125} \: ans$

Here is your solution. Thanks

Answer 2

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Question}}}}}}}}$

$\sf 5 . (81)^{0.16} \times (81)^{0.09}$

$\sf 6. ({\dfrac{64}{25}})^{\frac{-3}{2}}$

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Solution}}}}}}}}$

$\sf 5 . (81)^{0.16} \times (81)^{0.09}$

${\bold{\blue{\boxed{\bf{a^x \times a^y = a^{x+y} }}}}}$

$\sf\implies (81)^{0.09 + 0.16}$

$\sf\implies 81 ^{0.25}$

$\sf\implies {3} ^ {\cancel 4\times\frac{1}{ \cancel 4}}$

$\sf\implies 3$

${\bold{\blue{\boxed{\bf{\dag 3 }}}}}$

$\sf 6. {\dfrac{64}{25}}^{\frac{-3}{2}}$

$\sf \implies {\dfrac{8}{5}}^{\cancel 2\times{\frac{-3}{\cancel 2}}}$

${\bold{\blue{\boxed{\bf({\dfrac{a}{b}})^{-x} = ({\dfrac{b}{a}})^x }}}}$

$\sf\implies ({\dfrac{5}{8}})^3$

$\sf\implies\dfrac{125}{512}$

${\bold{\blue{\boxed{\bf{\dag \dfrac{125}{512} }}}}}$

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