please solve this question!
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i think your answer is 10.08L
vaidik31:
can you explain it?
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Helloo!!
Balanced Chemical Equation
2KClO3 --- 2KCl + 3O2
mass of 1 mole of KClO3 = 122.5g
1 mole occupies 22.4 litres at STP, thus 122.5g of KClO3 occupies 22.4 liters.
36.75 gm of KClO3 occupies 6.72 litres.
So,
2 volume KClO3 produces 3 Vol. of O2
6.72 liters of KClO3 will produce 6.72*3/2 liters of O2 = 10.08 ltr
hope this helps
Balanced Chemical Equation
2KClO3 --- 2KCl + 3O2
mass of 1 mole of KClO3 = 122.5g
1 mole occupies 22.4 litres at STP, thus 122.5g of KClO3 occupies 22.4 liters.
36.75 gm of KClO3 occupies 6.72 litres.
So,
2 volume KClO3 produces 3 Vol. of O2
6.72 liters of KClO3 will produce 6.72*3/2 liters of O2 = 10.08 ltr
hope this helps
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