please solve this question
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Kb=R/Na
Na=6.023×10^23 mol-1
R=8.31 Jmol-1/K
Kb=8.31 Jmol-1/K. /6.023×10^23 mol-1
Kb=1.38×10^-23 J/K
I hope this helps ( ╹▽╹ )
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