Math, asked by abcdefg79, 10 months ago

Please solve this question​

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Answered by pravatiswain3122
0

Answer:

I can't answer this question sorry

Answered by 217him217
1

Answer:

[ 5^(2n+2) * 4^(n+3) - 25^n * 2^(2n+4) ]/ [ 10^(2n+2) - 5^2n * 2^(2n+5) ]

= [ 5^(2n+2) * 2^(2n+6) - 5^2n* 2^(2n+4) ] / [ 10^(2n+2) - 5^2n * 2^(2n+5) ]

= 5^2n * 2^(2n+4) [ 5² * 2² - 1 ] / [ (5*2)^(2n+2) - 5^2n * 2^(2n+5) ]

= 5^2n * 2^(2n+4) [ 100-1] / [ 5^(2n+2) * 2^(2n+2) - 5^2n * 2^(2n+5) ]

=5^2n * 2^(2n+4)* 99 / 5^2n * 2^(2n+2) (1 - 8)

= 2^(2n+4-2n-2) * (99/-7)

=4*99/-7

= -(396/7)

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