Question

Please solve this question ​

Answer 1

Consider triangle ABC
• AB = 12 cm
• BC = 16 cm
• By pythagorus property , AB^2 + BC^2 = AC^2
12*12 + 16*16* ==> 400
root of 400 = 20 = AC
• AC = 20 cm


Now consider CDE
As above , apply Pythagorus , we obtain DE = 16 cm

comparing the two triangles
By SSS congruence criteria ,
triangle ABC =~ triangle CDE

Answer 2

AB=CD SIDE

Angle ABC=Angle CDE ANGLE

by pythagoras theorem we can find AC=20=CE SIDE

SO ANGLE ABC IS CONGRUENT TO ANGLE CDE BY SAS CONGRUENT RULE