Math, asked by rajsinghrajput4, 8 months ago

please solve this question ​

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Answered by deviv8390
3

Answer:

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Step-by-step explanation:

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Answered by snehakuriyal
0

Step-by-step explanation:

x'4-2x'2-3=0

x'4-(3-1)x'2-3=0

x'4-3x'2+x'2-3=0

x'2(x'2-3)+1(x'2-3)=0

(x'2-3) (x'2+1)=0

x'2-3=0. ,. x'2+1=0

x=√3. ,. x=√-1

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