please solve this question
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Step-by-step explanation:
x'4-2x'2-3=0
x'4-(3-1)x'2-3=0
x'4-3x'2+x'2-3=0
x'2(x'2-3)+1(x'2-3)=0
(x'2-3) (x'2+1)=0
x'2-3=0. ,. x'2+1=0
x=√3. ,. x=√-1
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