Math, asked by Krishshah8899, 8 months ago

please solve this question ​

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Answered by Anonymous
0

Answer:

( \sqrt[3]{ \frac{8}{27} } )^{2}  \div  (\sqrt[5]{32} )^{ - 2}  =  \\  \\  =  > (( \frac{ {2}^{3} }{ {3}^{3} } )^{ \frac{1}{3} } )^{2}  \div ((2 ^{5} )^{ \frac{1}{5} }) {}^{ - 2}  \\  \\  \\  =  >( ( \frac{2}{3})^{3 \times  \frac{1}{3} } ) {}^{2}  \div  ({2}^{5 \times  \frac{1}{5} } ) ^{ - 2}  \\  \\  \\  =  > ( { \frac{2}{3} })^{2}  \times  \frac{1}{ {2}^{2} }  \\  \\  =  >  \frac{4}{9} \times  \frac{1}{4}  =  \frac{1}{9}

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Answered by 27kanishka
0
Answer is 1/9
Hope the answer is helpful
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