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As it is isosceles triangle the the perpendicular AD bisect the base so,
BD=DC = 4cm
Area of ∆ABD = 1/2×base×height = 1/2× 4×3=6cm²
Similarly area of ∆ADC = 1/2×4×3= 6cm²
and area of ∆ ABC = 1/2×8×3 = 12cm²
Step-by-step explanation:
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Answer is 6...
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