Question

please solve this question...

Answer 1

Step-by-step explanation:

2x+10+x-5+x+y+15=180

4x+y=180-20

4x+y=160-------(i)

x-5+2y-10+x+y+15=180

2x+3y=180°----------(ii)

from i and ii

solve and find x and y

thanx

Answer 2

Here is the answer mate

Since AB || CD

angle APQ = angle PQR. [ alternate interior angles ]

》 2x + 10 = 2y - 10

》2x + 10 + 10 = 2y

》2x + 20 = 2y ............(1)

》 2 ( x + 10 ) = 2(y)

》 x + 10 = y ...... (2)

In triangle PQR, we have

angle P + angle Q + angle R = 180°

x - 5 + 2y - 10 + x + y + 15 = 180°

Now from (1) & (2) , we have

x - 5 + 2x + 20 + x + x + 10 + 15 = 180°

5x + 50 = 180

5x = 130

x = 26

Put x = 26 in (2) , we have

y = x + 10 = 26 + 10 = 36

Thus

y = 36

x = 26

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