Question

Please solve this question...

Answer 1

Heya User,

--> As you see.... 

--> AD = 6cm
--> ∠DAC = π/8 = 22.5° and ∠ACE = π/4 = 45°
=> ∠AGC = 112.5

Now, since two medians pass through point --> G .. G is centroid...
Hence, --> AG:GD = 2:1
========> AG = 4cm --> GD = 2cm

Now, from Sine Rule :--->
---> AC / sin AGC = AG / sin ACE
==> AC = AG sin AGC / sin ACE = AG sin 112.5° / sin 45° 
==> AC = 4 * sin [ 90 + 45/2 ] / sin 45°
==> AC = 4 * cos 45/2 / sin 45°
==> AC = 4 * 1.306 = 5.22 ...

Hence, Area of ADC = 1/2 * sin DAC * AD * AC 
--> [ ADC ] ≈ 6 sq. unit

Hence, --> [ ABC ] = 2[ ADC ] = 12 sq. unit <--- ANs...

Answer 2

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