Question

please solve this question​

Answer 1

Hm okay I will try best

38

Simply x=0.

→ 0a+0b+0c+d=0 → d=0

→ Polynomial is ax³+bx²+cx=x(ax²+bx+c)

Again, x=0 because two roots

→ 0a+0b+c=0 → c=0

→ Polynomial is x²(ax+b) → ∴Third zero is -b/a

39

Simply x=2.

→ 4+6+k=0 → k=-10

42

(d) is impossible since there are three zeros.