please solve this question
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Hi ,
Let ( x1 , y1 ) = A( 10cosA , 0 ) ;
( x2 , y2 ) = B ( 0 , 10sinA )
Distance = √( x2 - x1 )² + ( y2 - y1 )²
= √ ( 0 - 10cosA )² + ( 10sinA - 0 )²
= √ 10²cos²A + 10²sin²A
= √ 10² ( cos²A + sin² A )
= √ 10²
= 10
I hope this helps you.
:)
Let ( x1 , y1 ) = A( 10cosA , 0 ) ;
( x2 , y2 ) = B ( 0 , 10sinA )
Distance = √( x2 - x1 )² + ( y2 - y1 )²
= √ ( 0 - 10cosA )² + ( 10sinA - 0 )²
= √ 10²cos²A + 10²sin²A
= √ 10² ( cos²A + sin² A )
= √ 10²
= 10
I hope this helps you.
:)
mysticd:
Here I used A instead of theta.
Answered by
2
this may help a 10th standard
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