Question

Please solve this question ......................​

Answer 1

Answer:

In beaker A, a reddish brown layer of copper will deposit on the iron nail and the blue coloured solution will become yellowish green.

On the other hand, no change is observed in beaker B.

Explanation:

he Fe displaces the Cu from CuSO 4  solution in beaker A as Fe is more reactive than Cu.  

Therefore the blue colour of the solution changes to green due to the formation of FeSO  4

In beaker B, no reaction takes place as Cu being less reactive cannot displace Fe from FeSO  4 solution.

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Answer 2

Answer:

Your answer is given in above picture

Hope it help you

Radhe Radhe jay shree Krishna

# Riifam..