Question

please solve this question ​

Answer 1

Answer:

given ,=ba perpendicular ac

de perpendicular ef

ba=de

bf=ec

in triangle abc and def in which,

angle a= angle d(90 degree)

ba=de

bf =ec

abc =~ to def

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Answer 2

as bf=ce &cf is common

hence bc=ef

we got 2 line and one angle is same

hence, abc&def r Equilateral triangle

hope this is helpful