Math, asked by niteshshaw723, 8 months ago

please solve this question ​

Attachments:

Answers

Answered by Anonymous
1

Answer:

\huge\purple\star\underline\mathfrak\pink{See \: the \: attachment :-}\purple\star

Attachments:
Answered by Hemalathajothimani
7

Answer:

polynomial is 2x

4

−11x

3

+7x

2

+13x−7

\text{Sum of the zeros =}3+\sqrt{2}+3-\sqrt{2}=6Sum of the zeros =3+

2

+3−

2

=6

\text{Product of the zeros }Product of the zeros

=(3+\sqrt{2})(3-\sqrt{2})=(3+

2

)(3−

2

)

=3^2-(\sqrt{2})^2=3

2

−(

2

)

2

=9-2=7=9−2=72x^4-11x^3+7x^2+13x-7Given=(3+

2

)(3−

2

)

=3^2-(\sqrt{2})^2=3

2

−(

2

)

2

=9-2=7=9−2=7

\therefore\text{Corresponding factor is }\bf\,x^2-6x+7∴Corresponding factor is x

2

−6x+7

\text{Now,}Now,

2x^4-11x^3+7x^2+13x-7=(x^2-6x+7)(2x^2+px-1)2x

4

−11x

3

+7x

2

+13x−7=(x

2

−6x+7)(2x

2

+px−1)

\text{Equating coefficients of x on both sides we get }Equating coefficients of x on both sides we get

13=6+7p13=6+7p

7p=77p=7

\implies\,p=1⟹p=1

\therefore\text{Other factor is }\,2x^2+x-1∴Other factor is 2x

2

+x−1

2x^2+x-1=(2x-1)(x+1)2x

2

+x−1=(2x−1)(x+1)

\therefore\text{All zeros are }-1,\;\frac{1}{2},\;3+\sqrt{2},\;3-\sqrt{2}∴All zeros are −1,

2

1

,3+

2

,3−Find all the zeros of the polynomial ( 274 – 11x +77 + 13x - 7 ) , it being given that two of its zeros are ( 3 + 2 ) and ( 3-2 ) .

Step-by-step explanation:

Hii mate here is ur answer plz mark me as brainlist friend and thank me...plz give more thanks and get thanks don't forget to follow me #friend══════ •『 ♡』• ════════════ •『 ♡』• ═══════════

see this

══════ •『 ♡』• ════════════ •『 ♡』• ════════════

ƒσłłσω мε

GIVE THANKS = TAKE THANKS

Similar questions