Question

please solve this question​

Answer 1

Answer.

Let Meq of NaOH = x and let Meq of Na2CO3 = y

Meq of NaOH +1/2 Meq Na2CO3 = Meq HCl

x+ y /2 = 0.5 × 21 = 10.5 ................( i )

Meq Na2CO3 / 2 = Meq HCl

or, y / 2 = 0.5× 7

or, y = 7

Now, Na2CO3 / ( 106 / 2 ) × 100 = y

or, Na2CO3 = 0.371