Question

please solve this question​

Answer 1

Answer:

Given that:

BOD is a diameter.

∠COD=92

∘

,∠ABD=65

∘

To find:

y=?

Solution:

In △ABD

∠ABD+∠BAD+∠ADB=180

∘

(Sum of angles of a triangle is equal to 180

∘

.)

or, 65

∘

+90

∘

+∠ADB=180

∘

or, ∠ADB=180

∘

−155

∘

=25

∘

or, ∠ADB=∠ADE=25

∘

Now,

∠CAD=

2

∠COD

(Angle at the centre is twice of angle at the circumference by a chord.)

or, ∠CAD=∠EAD=

2

92

∘

=46

∘

Now,

∠CEO=∠EAD+∠ADE (Sum of remote interior angles is equal to exterior angle.)

or, ∠CEO=46

∘

+25

∘

=71

∘

Again,

∠CEO+∠ECO=∠COD (Sum of remote interior angles is equal to exterior angle.)

or, 71

∘

+y=92

∘

or, y=21

∘

Hence, D is the correct option.

Answer 2

Answer:

The answer is d) 21 . y is equals to 21