Question

Please solve this question ​

Answer 1

Solution

Given :-

• √[(1 + sin A)/(1 - sin A)] = sec A + tan A

Find :-

• Prove that L.H.S. = R.H.S.

Step - by - Step - Explanation

For prove this, we have to One Method .

Solve L.H.S. and get R.H.S. in this way, we can prove this.

So, Take L.H.S.,

➡√[(1 + sin A)/(1 - sin A)]

Multiply by (1 + sin A) Numerator & Denominator .

➡ √[(1 + sin A)(1 + sin A)/(1 + sin A)(1 - sin A)]

[ (a+b)(a-b) = (a² - b²) ]

➡√[(1 + sin A)²/(1² - sin² A)]

[ (1 - sin² A) = cos² A ]

➡√[(1 + sin A)²/(cos² A)]

➡ (1 + sin A)/cos A

➡1/cos A + sin A/cos A

we Have,

✔ 1/cos A = sec A

✔sin A/cos A = tan A

So,

➡ sec A + tan A

= R.H.S.

That's proved

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Answer 2

Answer:

hope this will help u ❤️