Question

please solve this question​

Answer 1

Answer:

The sum of all angles of a triangle =180°

The sum of all angles of a triangle =180°Angle CAB=32°(vertically opposite angle)

The sum of all angles of a triangle =180°Angle CAB=32°(vertically opposite angle)Therefore,

The sum of all angles of a triangle =180°Angle CAB=32°(vertically opposite angle)Therefore,(x+14)°+90°+(x+32)°=180°

The sum of all angles of a triangle =180°Angle CAB=32°(vertically opposite angle)Therefore,(x+14)°+90°+(x+32)°=180°》2x=180°-14°-90°-32°

The sum of all angles of a triangle =180°Angle CAB=32°(vertically opposite angle)Therefore,(x+14)°+90°+(x+32)°=180°》2x=180°-14°-90°-32°》2x=44°

The sum of all angles of a triangle =180°Angle CAB=32°(vertically opposite angle)Therefore,(x+14)°+90°+(x+32)°=180°》2x=180°-14°-90°-32°》2x=44°》x=22°