Question

please solve this question

Answer 1

HELLO DEAR

$\frac{ \tan(65) }{ \cot(25) } \\ = > \frac{ \tan(90 - 25) }{ \cot(25) } \\ = > \frac{ \cot(25) }{ \cot(25) } using \: ( \tan(9 0 - theta) = \cot(theta) \\ = > 1$
I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Hi friend
here's the answer hope this helps you..
:) :)