please solve this question
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According to circle theorem,
QR.PR = SR.TR
Given, QR = 3 cm ,
PR = PQ + QR
= (5cm + 3cm) = 8 cm
SR = 2cm and
TR = TS + SR = (x + 2)cm
Now, 3cm × 8cm = 2cm × (x +2)cm
12cm = (x + 2)cm
x = 12 - 2 cm = 10cm
hence, x = 10cm
QR.PR = SR.TR
Given, QR = 3 cm ,
PR = PQ + QR
= (5cm + 3cm) = 8 cm
SR = 2cm and
TR = TS + SR = (x + 2)cm
Now, 3cm × 8cm = 2cm × (x +2)cm
12cm = (x + 2)cm
x = 12 - 2 cm = 10cm
hence, x = 10cm
Anonymous:
Good you got it finally. but guess my answer was in Hebrew, wasn't it?
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