Please solve this question
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alpha = 3 + sq.root5
beeta = 3 - sq.root5
alpha * beeta = c/a
(3 + sq.root5)(3 - sq.root5) = c/a
3^2 - (sq.root5)^2 = c/a
9 - 5 = c/a
c/a = 4
and,
alpha + beeta = -b/a
3 + sq.root5 + 3 - sq.root5 = -b/a
-b/a = 6
equation = x^2 - 6x + 4 = 0 ANSWER.
thanks...
beeta = 3 - sq.root5
alpha * beeta = c/a
(3 + sq.root5)(3 - sq.root5) = c/a
3^2 - (sq.root5)^2 = c/a
9 - 5 = c/a
c/a = 4
and,
alpha + beeta = -b/a
3 + sq.root5 + 3 - sq.root5 = -b/a
-b/a = 6
equation = x^2 - 6x + 4 = 0 ANSWER.
thanks...
Rahul1905:
thanks bilal for marking it the brainliest
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Please mark as brain list .Hope it helps.
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