Question

please solve this question​

Answer 1

Step-by-step explanation:

${2}^{ {2x}^{2} - 7x + 5 } = 1$

It is of the form

$y = {b}^{x}$

where

it can be written as

$x = log_{y}(b)$

so,

${2x}^{2} - 7x + 5 = log_{2}(1)$

and we also know that log 1 is 0

so,

$2 {x}^{2} - 7x + 5 = 0$

solving it,

${2x}^{2} - 2x - 7x + 5 = 0$

$2x(x - 1) - 5x(x - 1) = 0$

$(x - 1)(2x - 5) = 0$

$x = 1 \: or \: x = \frac{5}{2}$

hence the values of x are 1 and 5/2

HOPE YOU GOT IT