Question

please solve this question. ​

Answer 1

Answer:

understood

I hope this answer is your helpful

Answer 2

Answer:

$( {3}^{ - 1} + {4}^{ - 1} )( \frac{7}{12} ) {}^{ - 1} \\ \\ = (\frac{1}{3 {}^{ 1} } + \frac{1}{4 {}^{1} } )( \frac{12}{7}) {}^{1} \\ \\ (\frac{1 + 1}{12} )( \frac{12}{7} ) \\ \\ ( \frac{4 + 3}{12})( \frac{12}{7} ) \\ \\ \frac{7}{12} \times \frac{12}{7} \\ \\ = \frac{84}{84 } \\ \\ = 1$