Question

please solve this question​

Answer 1

Answer:

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Answer 2

Answer:

Let the two-digit number be AB.

When we reverse this number, it becomes BA and BA - AB = 9 (it is given that the new number is greater than the original number by 9)

Now, AB can be written in the expanded form as 10A + B

Similarly BA = 10B + A

Now, BA - AB = 9

⇒(10B + A) - (10A + B) = 9

⇒10B + A - 10A - B = 9

⇒9B - 9A = 9

⇒9(B - A) = 9

⇒B - A = 1

Now A + B = 15 and B - A = 1

(A + B) + (B - A) = 15 + 1

⇒ A + B + B - A = 16

⇒2B = 16

⇒B = 8

Putting B = 8 in B - A = 1, we get

8 - A = 1

⇒1 + A = 8

⇒A = 8 - 1 = 7

The original number = 10A + B = 10(7) + 8 = 70 + 8 = 78

Hence, the original number = 78

I hope that it helps

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