Question

PLEASE SOLVE THIS QUESTION​

Answer 1

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$\cot(a) = \frac{40}{9} \\ = > \frac{ \cos(a) }{ \sin(a) } = \frac{40}{9} \\ = > \frac{1}{ \sin(a) } = \frac{40}{9 \times \cos(a) } \\ = > \csc(a) = \frac{40}{9} \sec(a)$

Answer 2

cot x = cosx/sinx........