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x²-4x+3
=x²-x-3x+3
=x(x-1)-3(x-1)
=(x-3)(x-1)
x=1,3
So,α=1 and β=3.
α⁴β²+α²β⁴=α²β²(α²+β²)
=1²ₓ3²(1²+3²)
=9(1+9)
=9ₓ10
=90
=x²-x-3x+3
=x(x-1)-3(x-1)
=(x-3)(x-1)
x=1,3
So,α=1 and β=3.
α⁴β²+α²β⁴=α²β²(α²+β²)
=1²ₓ3²(1²+3²)
=9(1+9)
=9ₓ10
=90
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