Question

please solve this question .....

Answer 1

Let time taken by tap with smaller diameter to fill tank = x hours
Work done in 1 hour = 1/x
time taken by tap with bigger diameter to fill tank = (x - 10) hours
Work done in 1 hour = 1/(x - 10)
1/x + 1/(x - 10) = 8/75

8x^2 - 230x + 750 = 0
4x^2 - 115x + 375 = 0
4x^2 - 100x - 15x + 375 = 0

x = 25 or x = 3.75
x = 3.75 rejected because then x - 10 < 0
So x = 25
Time taken by pipes are 25 hours and 15 hours(ans)


let the small pipe take x hours then larger pipe take x-10 hours to fill seperately

then 1/x+/x-10 = 8/75

2x-10/x²-10x= 8/75

150x-750 =8x²80x

8x²-230x+750=0

4x²-1150X+375 =0

SOLVING X=25,15/4

BUT 15/4 IS NOT POSSIBLE (15/4-10 < 0)

X= 25 ,X-10 =15

HOPE YOU UNDERSTAND

Answer 2

Answer:

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