Question

please solve this question​

Answer 1

the given equation is

${9}^{x} \times {3}^{2} \times ({3}^{ - x \div 2} )^{ - 2} = \frac{1}{27}$

it can be written as

${3}^{2x} \times {3}^{2} \times {3}^{x} = {3}^{ - 3} \\ {3}^{2x + 2 + x} = {3}^{ - 3} \\ {3}^{3x + 2} = {3}^{ - 3}$

now, since bases are same , then comparing the powers,we get

3x+2= -3

$x = \frac{ - 5}{3}$

I hope this helps u ☺️