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In triangle QBX and triangle PAX,
i)Angle BXQ = Angle PXA (vertically opposite angles)
ii)Angle XAP = Angle BQX(alternate angles
iii)QB=AP(As OA=OB and OP =OQ)
Therefore........
Triangle QBX congruent triangle PAX
Therefore......
PX = QX(CPCT)
AX=BX(CPCT
a)PX = QX (proved above)Proved
b)AX=BX(proved above)proved
Hope this helps.....
i)Angle BXQ = Angle PXA (vertically opposite angles)
ii)Angle XAP = Angle BQX(alternate angles
iii)QB=AP(As OA=OB and OP =OQ)
Therefore........
Triangle QBX congruent triangle PAX
Therefore......
PX = QX(CPCT)
AX=BX(CPCT
a)PX = QX (proved above)Proved
b)AX=BX(proved above)proved
Hope this helps.....
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