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9b² - 3c² and 2b² + bc - 2c² subtraction 2b² - 2 bc - c² and c² + 2bc - b²
Step-by-step explanation:
(9b² - 3c² = 2b² + bc -2c²) - ( 2b² - 2 bc - c² = c² + 2bc - b²)
= ( 9b² - 2b² - 3c² + 2c² - bc) - ( 2b² + b² - 2bc - 2bc - c² - c² )
= ( 7b² - c² - bc ) - ( 3b² - 4bc -2c²)
= ( 7b² - c² - bc ) - ( 3b² - 4bc - 2c²) = 0
= ( 7b² - c² - bc ) = ( 3b² - 4bc - 2c²)
= 7b² - 3b² - c² +2c² - bc + 4bc
= 4b² - c² - 3bc
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