please solve this question
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use the formula of triangle and equate it to zero. substitute the given values.the formula: x1(y2- y3)+ X2( y3-y1)+X3(y1- y2)= 0
=a(b^2-0)+b(0-a^2)+0(a^2-b^2)
=ab^2+(-a^2b)+0
= ab^2-a^2b
=a(b^2-ab)
hope it helps :) please mark it as brainliest
=a(b^2-0)+b(0-a^2)+0(a^2-b^2)
=ab^2+(-a^2b)+0
= ab^2-a^2b
=a(b^2-ab)
hope it helps :) please mark it as brainliest
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