Question

please solve this question

523dc655585581ae59e09c0f1ecb5dec.docx

Answer 1

Answer:

2) $\frac{4\sqrt{3} }{2-\sqrt{2} } - \frac{30 }{4\sqrt{3} - 3\sqrt{2} } - \frac{3\sqrt{3} }{3+2\sqrt{3} }$ = $\frac {-60\sqrt{3}}{1 - 2\sqrt{2} +6\sqrt{3} }$

3) $\frac{2^{30} + 2^{29} + 2^{28} }{2^{31} + 2^{30} - 2^{29} }$ = $\frac{7} {10}$ = 7/10 = 0.7

Step-by-step explanation:

2) $\frac{4\sqrt{3} }{2-\sqrt{2} } - \frac{30 }{4\sqrt{3} - 3\sqrt{2} } - \frac{3\sqrt{3} }{3+2\sqrt{3} }$

 = 1 ÷ $(\frac{2-\sqrt{2}}{4\sqrt{3}} - \frac{4\sqrt{3} - 3\sqrt{2} }{30} - \frac{3+2\sqrt{3} }{3\sqrt{3} })$

 = 1 ÷ $(\frac{(2-\sqrt{2}) - (4\sqrt{3} - 3\sqrt{2}) - (3+2\sqrt{3})}{60\sqrt{3}} )$

 = 1 ÷ $(\frac{2-\sqrt{2} -4\sqrt{3} + 3\sqrt{2} -3-2\sqrt{3}}{60\sqrt{3}} )$

 = 1 ÷ $(\frac{2 -3 -\sqrt{2} + 3\sqrt{2} -4\sqrt{3} -2\sqrt{3}} {60\sqrt{3}} )$

 = 1 ÷ $(\frac{-1 + 2\sqrt{2} -6\sqrt{3} } {60\sqrt{3}} )$

 = $\frac {60\sqrt{3}}{-1 + 2\sqrt{2} -6\sqrt{3} }$

 = $\frac {-60\sqrt{3}}{1 - 2\sqrt{2} +6\sqrt{3} }$

 = but this answer is not sure for me

3) $\frac{2^{30} + 2^{29} + 2^{28} }{2^{31} + 2^{30} - 2^{29} }$

  = $\frac{2^{28}(2^{2} + 2^{1} + 1 )} {2^{29} (2^{2} + 2^{1} - 1)}$

  = $\frac{1(2^{2} + 2^{1} + 1 )} {2^{1} (2^{2} + 2^{1} - 1)}$

  = $\frac{(4 + 2 + 1 )} {2(4 + 2 - 1)}$

  = $\frac{7} {2(5)}$

  = $\frac{7} {10}$

  = 7/10

  = 0.7