Question

please solve this question. ​

Answer 1

Answer:

(1/2)‐³ + (1/3)‐² = 9/2

Answer 2

${ (\frac{1}{2}) }^{ - 3} + { (\frac{1}{3}) }^{ - 2}$

$\frac{ {(1)}^{ - 3} }{ {(2)}^{ - 3} } + \frac{ {(1)}^{ - 2} }{ {(3)}^{ - 2} }$

$\frac{ \frac{1}{ {1}^{3} } }{ \frac{1}{ {2}^{3} } } + \frac{ \frac{1}{ {1}^{2} } }{ \frac{1}{ {3}^{2} } }$

$\frac{1}{ {1}^{3} } \times \frac{ {2}^{3} }{1} + \frac{1}{ {1}^{2} } \times \frac{ {3}^{2} }{1}$

$\frac{1}{1} \times \frac{8}{1} + \frac{1}{1} \times \frac{9}{1}$

$8 + 9$

$17$

When there is a negative sign for the power , we will write the reciprocal of the number.

That is , for eg : 3‐²=1/3²

$\purple{ \tt{Hope \: \: this \: \: helps \: \: you \: !}}$