Question

Please solve this question​

Answer 1

Answer:

taking left hand side equation

1+tan^2A/(1+secA)

using identity, 1+ tan^2A=sec^2A

so,

1+ (sec^2A-1)/(secA+1)

using identity,(a^2-b^2)=(a-b)×(a+b)

hence,

1+ (secA-1)×(secA+1)/(secA+1)

=1+ secA-1

= secA

which is equal to right hand side