Question

Please solve this question

Answer 1

Correct Question

=> The taxi fare in a town is Rs.10 for the first km and Rs.6 per km for the subsequent distance. Taking distance as 'x' km and the total fare as Rs 'y' , write a linear equation for this information, what will be the total fare for 15 km?

Solution:-

Given

=> Taxi Fare for first km = 10rs

=> For subsequent distance 6rs per km

Let total distance be x

=> For 1 km taxi fare is 10 rs

We can write as 10 × 1 = 10 rs

=> For Subsequent distance ( x - 1 ) taxi fare is 6 rs

We get 6( x - 1 ) rs

Total Fare(y) will be

=> y = 10 + 6( x - 1 )

=> y = 10 + 6x - 6

=> y = 4 + 6x

Linear equation is => y = 4 + 6x

Now we have to find total fare for 15km

=> So we get x = 15 km

Put the value on equation

=> y = 4 + 6x

Where x = 15km

=> y = 4 + 6 × 15

=> y = 4 + 90

=> y = 94

So Total fare for 15km is Rs 94

Answer 2

Given :-

• For the first kilometre, taxi fare = Rs. 10

• For the next subsequent kilometre, taxi fare = Rs. 6 per kilometre

• Total distance is 'x'

• Total fare is 'y'

To find :-

• Linear equation for given information

• Total fare for 15 km

Solution :-

Forming the linear equation :-

For the first kilometre, taxi fare is 10 Rs and for next subsequent kilometre, taxi fare is Rs. 6

Take fare for 1 km = Rs. 10

Total distance is 'x'

So, for subsequent kilometre, distance will be ( x - 1 )

Taki fare for ( x - 1 ) = Rs. 6 ( x - 1 )

Total fare = fare for 1 km + fare for ( x - 1 ) km

➩ y = 10 + 6 ( x - 1 )

➩ y = 10 + 6x - 6

➩ y = 6x + 10 - 6

➩ y = 6x + 4

Linear equation, y = 6x + 4

Calculating fare for 15 km :-

We have now the linear equation as y = 6x + 4, as we have to find fare for 15 km, distance = 15 km.

x = 15 km

Now, by simply substituting the value in linear equation -

➩ y = 6x + 4

➩ y = 6 × 15 + 4

➩ y = 90 + 4

➩ y = 94

Total Fare for 15 km = Rs. 94