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Heyà !!
Given, secA + tanA = x
Thus, secA = x – tanA
Given, secA + tanA = x
Thus, secA = x – tanA
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hey dear
here is your answer
solution
Sec theta = x - Tan theta
squaring on both the sides
Sec^2 theta = x^2 - 2* x * tan theta + tan^2 theta
Sec^2 theta - Tan ^2 theta = x^2 -2* x* Tan theta
x^2 - 2* x * Tan theta - 1 = 0
2* x* Tan theta = x^2 -1
Tan theta = ( x^2 - 1/2x ) ( sec theta = tan theta)
we can write also like this
sec theta value = ( x^ _ 1/2x)
it is the answer
hope it helps
thank you
here is your answer
solution
Sec theta = x - Tan theta
squaring on both the sides
Sec^2 theta = x^2 - 2* x * tan theta + tan^2 theta
Sec^2 theta - Tan ^2 theta = x^2 -2* x* Tan theta
x^2 - 2* x * Tan theta - 1 = 0
2* x* Tan theta = x^2 -1
Tan theta = ( x^2 - 1/2x ) ( sec theta = tan theta)
we can write also like this
sec theta value = ( x^ _ 1/2x)
it is the answer
hope it helps
thank you
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