Question

please solve this question​

Answer 1

$\sf{Answer}$

Given :-

Sides of triangle

• 3x²+2x-1
• 4x²+x+4
• 5x²+3x-2

To find :-

Perimeter of triangle

Concept:-

Perimeter is nothing but sum of all sides that means total length of all sides

So, they given sides If we add those we get perimeter

Perimeter= a+b+c

Solution:-

Let

A = 3x²+2x-1

B = 4x²+x+4

C = 5x²+3x-2

So, perimeter = A+B+C

3x² + 2x - 1 + 4x² + x + 4 + 5x² + 3x -2

Put like terms together

3x² + 4x² + 5x² + 2x + x + 3x -1 + 4 -2

12x² + 6x + 4 - 3

12x² + 6x + 1

So, perimeter of triangle is 12x² + 6x + 1

Know more :-

Perimeter of square = 4a

Perimeter of rectangle = 2(l+b)

Perimeter of rhombus = 4a

Perimeter of isosceles triangle = 2a+b

Perimeter of equilateral triangle = 3a

Perimeter of parallelogram = 2 (a+b)

Answer 2

Given :-

Sides of triangle

3x²+2x-1

4x²+x+4

5x²+3x-2

To find :-

Perimeter of triangle

Concept:-

Perimeter is nothing but sum of all sides that means total length of all sides

So, they given sides If we add those we get perimeter

Perimeter= a+b+c

Solution:-

Let

A = 3x²+2x-1

B = 4x²+x+4

C = 5x²+3x-2

So, perimeter = A+B+C

3x² + 2x - 1 + 4x² + x + 4 + 5x² + 3x -2

Put like terms together

3x² + 4x² + 5x² + 2x + x + 3x -1 + 4 -2

12x² + 6x + 4 - 3

12x² + 6x + 1

So, perimeter of triangle is 12x² + 6x + 1

Know more :-

Perimeter of square = 4a

Perimeter of rectangle = 2(l+b)

Perimeter of rhombus = 4a

Perimeter of isosceles triangle = 2a+b

Perimeter of equilateral triangle = 3a

Perimeter of parallelogram = 2 (a+b)