Math, asked by srivastavaanuradha07, 4 months ago

please solve this question​

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Answered by Dinosaurs1842
0

 \dfrac{x - 3}{2} + 4  = \dfrac{3x + 7}{4}

Method 1 :

By taking LCM for the LHS (Left hand side),

 \dfrac{(x - 3) + 4(2)}{2}  =  \dfrac{3x + 7}{4}

 \dfrac{x - 3 + 8}{2}  =  \dfrac{3x + 7}{4}

By adding the constants in the LHS (Left hand side)

 \dfrac{x + 5}{2}  =  \dfrac{3x + 7}{4}

By cross multiplication,

4(x + 5) = 2(3x + 7)

4x + 20 = 6x + 14

Bringing all the constants to one side and variables to the other,

20 - 14 = 6x - 4x

6 = 2x

 \dfrac{ \not6}{ \not2}  = x

3 = x

Verification :-

By substituting x for 3,

 \dfrac{x  +  3}{2}   + 4 =  \dfrac{3x + 7}{4}

 \dfrac{3 - 3}{2}  + 4 =  \dfrac{3(3) + 7}{4}

 \dfrac{0}{2}  + 4 =  \dfrac{9 + 7}{4}

4 =  \dfrac{16}{4}

LHS = RHS

Hence verified

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