please solve this question
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Answer:
Total sweets = 48
No. of sweets given to Jai = 15
No. of sweets given to Dhruv = 13
No. of sweets left to Tarun = 48 - ( 15+13)
= 48 - 28
= 20 sweets
No fraction of sweets left to Tarun with no of original sweets is
= 20/48
= 5/12
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Answered by
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Answer:
tarun has:48 sweets
he gave:15+13=28
48-28+20
20/48 sweets are left
20/48x2= 40/98
20/48x3=60/144
Step-by-step explanation:
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