Question

please solve this question

Answer 1

Hey here is your answer
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${x}^{2} + 4 \sqrt{3} x + 9 = 0 \\ \\ the \: relation \: between \: the \: zeros \: . \\ \\ sum \: of \: the \: zeros \: \\ ( \alpha + \beta ) = \frac{ - b}{c} = \frac{ - 4 \sqrt{3} }{1} \\ \\ product \: of \: the \: zeros \: \\ \alpha \beta = \frac{c}{a} = \frac{9}{1}$
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Answer 2

comparing the given eqation with
$ax {}^{2} + bx + c = 0$
we get a= 1
b=−4√​3​​​
c=9
Therefore
the sum of the root is =
$- \frac{b}{a} = - \frac{ - 4 \sqrt{3} \} }{1} = 4 \sqrt{3}$

Root of the equation =
$\frac{c}{a} = \frac{9}{1} = 9$