please solve this question
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Solution
Given :-
- sin²θ/(tan² θ - sin² θ) = 3
Find :-
- Value of theta (θ)
Explanation
Given that,
==> sin²θ/(tan² θ - sin² θ) = 3
==> sin² θ = 3 × ( tan² θ - sin² θ)
==>sin² θ = -3sin² θ + 3 tan² θ
==> sin² θ + 3 sin² θ = 3 tan² θ
==> 4sin² θ = 3 tan² θ
Using Formula
★ tan θ = sin θ/cos θ
==> 4 sin² θ = 3 sin² θ/cos² θ
==> cos² θ = 3/4
==> cos θ = √(3/4)
==> cos θ = √3/2
Wr Know,
★ cos 30° = √3/2
so,
==> cos θ = cos 30°
==> θ = 30°
Hence
- Value of θ will be = 30°
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