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★ Hey there !!! ★
here is your answer !!!
look this attachment :-
thanks
here is your answer !!!
look this attachment :-
thanks
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Logical Method :
Steps :
1) To get the polynomial whose roots are Just inverse of the original one.
Replace x with 1/x .
Here, Original Equation.
Now, Replace t with 1/t .
We get,
(1/t)^2 -(1/t) -4=0
=> 1 - t -4t^2 =0
=> 4t^2+t -1 =0
Required Polynomial is
4t^2 +t - 1
Steps :
1) To get the polynomial whose roots are Just inverse of the original one.
Replace x with 1/x .
Here, Original Equation.
Now, Replace t with 1/t .
We get,
(1/t)^2 -(1/t) -4=0
=> 1 - t -4t^2 =0
=> 4t^2+t -1 =0
Required Polynomial is
4t^2 +t - 1
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