Question

Please solve this question

Answer 1

Given Equation is : x - y = 13 

x = 13 + y  ----- (1)

$Given : \sqrt{x} + \sqrt{y} = 13 --- (2)$

Substitute (1) in (2), we get 

$= \ \textgreater \ \sqrt{13 + y} + \sqrt{y} = 13$

$= \ \textgreater \ \sqrt{13 + y} = 13 - \sqrt{ y}$

On squaring both sides, we get

$= \ \textgreater \ ( \sqrt{13 + y})^2 = (13 - \sqrt{y} )^2$

$= \ \textgreater \ 13 + y = 169 + y - 26 \sqrt{y}$

$= \ \textgreater \ -156 = -26 \sqrt{y}$

On squaring both sides, we get

$= \ \textgreater \ (-156)^2 = (-26 \sqrt{y} )^2$

= > 24336 = 676y

= > y = 24336/676

= > y = 36.


Substitute y = 36 in (1), we get

= > x = 13 + y

= > x = 13 + 36

= > x = 49.



Therefore the value of x = 49 and y = 36.


Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks