Question

please solve this question ​

Answer 1

Answer:

$3^\frac{-3}{5}$

Step-by-step explanation:

$(\frac{27^{-3} }{9^{-3}} ) ^{\frac{1}{5}}$

= $(\frac{9^{3}}{27^{3} } ) ^{\frac{1}{5}}$

= $(\frac{9}{27 } )^{3 ^{\frac{1}{5}}}$

= $(\frac{1}{3} )^\frac{3}{5}$

= $3^\frac{-3}{5}$

Answer 2

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀${ \tt \bigg(\frac{ {27}^{ - 3} }{ {9}^{ - 3} } \bigg)}^{ \frac{1}{5} } \\ \\ { \tt \bigg(\frac{ {9}^{ 3} }{ {27}^{ 3} } \bigg)}^{ \frac{1}{5} } \\ \\ { \tt \bigg(\frac{ { ({3}^{2} })^{ 3} }{ { ({3}^{3}) }^{ 3} } \bigg)}^{ \frac{1}{5} } \\ \\ { \tt \bigg(\frac{ {3}^{ 6} }{ {3}^{ 9} } \bigg)}^{ \frac{1}{5} } \\ \\ { \tt \bigg(\frac{1 }{ {3}^{ 3} } \bigg)}^{ \frac{1}{5} } \\ \\ { \tt \bigg({ {3}^{ - 3 \times \frac{1}{5} } } \bigg)} \\ \\ \tt {3}^{\frac{ - 3}{5} }$