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Given that one zero is the polynomial of other
Let one zero be= alpha
Than 2 zero will =1/alpha
Now
ATQ
Product of zeroes =b/a
Alpha×1/alpha=6a/a^2+9
(NOTE:alpha will cancel out alpha so 1 will left on LHS)
1= 6a/a^2+9
a^2+9=6a
a^2 -6a+9=0
(a - 3)^2=0
a -3=0
a=3 is answer
Hope it help
So
Mark it as brainlest
Let one zero be= alpha
Than 2 zero will =1/alpha
Now
ATQ
Product of zeroes =b/a
Alpha×1/alpha=6a/a^2+9
(NOTE:alpha will cancel out alpha so 1 will left on LHS)
1= 6a/a^2+9
a^2+9=6a
a^2 -6a+9=0
(a - 3)^2=0
a -3=0
a=3 is answer
Hope it help
So
Mark it as brainlest
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