Math, asked by prabhanshkumar1969, 4 hours ago

please solve this question

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Answered by Athul4152
11

ANSWER = 4r/ s⁴

 \frac{3r {}^{ - 2} s {}^{3} }{ \: 12r {}^{ - 3} s {}^{7} } =  \frac{ {3s}^{ - 2} }{ {12r}^{ - 3} } \times  \frac{ {s}^{3} }{ {s}^{7} }   \\

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{ {12r}^{3} }{ {3r}^{2} }  \times  \frac{1}{ {s}^{4} }  \\

  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: =  \frac{4r}{ {s}^{4} }  \\

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