Question

please solve this question ​

Answer 1

If 2∧a=3∧b=6∧c, then prove that c=ab/a=b

let 2∧a=3∧b=6∧c=d

so,2∧a=d

⇒d∧1/a=2----------------eq 1.

and 3∧b=d

⇒d∧1/b=3----------------eq 2.

and also 6∧c=d

⇒d∧1/c=6-----------------eq 3.

we know that 6=2×3-----------------eq 4.

now put value of 2, 3 and 6 from eg. 1,2 and 3

we get d∧1/a × d∧1/b = d∧1/c

d(1/a=1/b) = d∧1/c

so, 1/c = 1/a + 1/b ⇒1/c = (b+a) / (ab)

⇒c=ab / a+b hence proved

Answer 2

Step-by-step explanation:

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