Question

Please solve this question​

Answer 1

Answer:

$\frac{1}{2 + \sqrt{3} } + \frac{2}{ \sqrt{5} - \sqrt{3} } + \frac{1}{2 - \sqrt{5} } \\ = \frac{1(2 - \sqrt{3} }{(2 + \sqrt{3} ))(2 - \sqrt{3}) } + \frac{2( \sqrt{5} + \sqrt{3} }{ (\sqrt{5} - \sqrt{3} )( \sqrt{5} + \sqrt{3} ) } + \frac{1(2 + \sqrt{5} )}{(2 - \sqrt{5})(2 + \sqrt{5} )} \\ = \frac{2 - \sqrt{3} }{ {2}^{2} - { \sqrt{3} }^{2} } + \frac{2( \sqrt{5} + \sqrt{3} )}{ { \sqrt{5} }^{2} - { \sqrt{3} }^{2} } + \frac{2 + \sqrt{5} }{ {2}^{2} - { \sqrt{5} }^{2} } \\ = \frac{2 - \sqrt{3} }{4 - 3} + \frac{2( \sqrt{5} + \sqrt{3} ) }{5 - 3} + \frac{2 + \sqrt{5} }{4 - 5} \\ = 2 - \sqrt{3} + \sqrt{5} + \sqrt{3} - 2 - \sqrt{5} \\ = 0$

Answer 2

Answer:

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