Math, asked by ankushkjapla, 1 month ago

please solve this question​

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Answered by 123UDAY123
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Answer:

firstly

in parallelogram PQRS

ANGLE Q = ANGLE S = 60° (opposite angles of the parallelogram are equal)

ANGLE P = ANGLE R = x (opposite angles of the parallelogram are equal)

ANGLE P + Q + R + S = 360 (angle sum property if the quadrilateral)

x + 60 + x + 60 = 360

2x = 360 - 120

2x = 240

x = 240/2

x = 120°

ANGLE P = 120°

ANGLE Q = 60°

ANGLE R = 120°

ANGLE S = 60°

SIMILARLY IN PARALLELOGRAM LMNQ

ANGLE Q = ANGLE M = 60° (opposite angles of the parallelogram are equal)

ANGLE L = ANGLE N = x (opposite angles of the parallelogram are equal)

ANGLE L + M + N + Q = 360 (angle sum property if the quadrilateral)

x + 60 + x + 60 = 360

2x = 360 - 120

2x = 240

x = 240/2

x = 120°

ANGLE L = 120°

ANGLE M = 60°

ANGLE N = 120°

ANGLE Q = 60°

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